Grade 4 Quadrilaterals and Parallel Lines
Two rules do almost all of the work here: a straight line is 180 degrees and a quadrilateral closes on 360. What makes these hard is carrying an angle two or three steps across a pair of parallel lines.
What this problem type covers
Nineteen problem types across five levels: three lines meeting at a point with two of them perpendicular, the distance across three parallel lines, two inside angles that add to 180, a bend between two parallels, three squares joined in a step, four rectangles making a square with a square hole, a parallelogram with an isosceles triangle on its side, a parallelogram with a triangle on its base, a parallelogram joined to a rhombus, a bent line between parallels with a perpendicular dropped in, two perpendiculars from a point inside a parallelogram, two lines crossing between parallels, folded rectangular paper, a trapezoid with two isosceles triangles, a zigzag with two turns, counting the rectangles that contain a star, counting the sizes of square a dot array allows, folded rhombus paper, and the difference between two angles a triangle makes across parallels.
Example problems
One example from each difficulty band, with worked solutions.
これらの問題は自動生成されています。解答は問題の作成時に決まりテストで検証していますが、誤りがある可能性があります。見つけたらお知らせください。
- 1 · ★1Lines 가, 나 and 다 are all parallel. How far apart are 가 and 다?
- ①35 cm
- ②39 cm
- ③31 cm
- ④43 cm
- ⑤11 cm
Show solution
③31 cm- The distance between two parallel lines is measured along a perpendicular.
- 가 to 나 is 10 cm and 나 to 다 is 21 cm.
- So 가 to 다 is 10 + 21 = 31 cm.
- A length measured at a slant is not the distance between the lines.
- 2 · ★2Four identical rectangles are joined without overlapping. What is the difference between the perimeter of the outer square and that of the inner one?
- ①12 cm
- ②96 cm
- ③72 cm
- ④48 cm
- ⑤24 cm
Show solution
④48 cm- The outer square has sides of 6 + 12 cm, so its perimeter is 72 cm.
- The inner square has sides of 12 − 6 cm, so its perimeter is 24 cm.
- The difference is 72 − 24 = 48 cm.
- 3 · ★3Lines 가 and 나 are parallel. How big is ㉮?
- ①67 degrees
- ②35 degrees
- ③113 degrees
- ④99 degrees
- ⑤58 degrees
Show solution
②35 degrees- Drop a perpendicular from one line to the other to make a quadrilateral.
- A straight line is 180, so the angle beside the perpendicular is 90 − 32.
- A quadrilateral closes on 360, so the remaining angle is 360 − (90 − 32) − 90 − 67.
- A straight line is 180, so ㉮ is 67 − 32 = 35 degrees.
- 4 · ★4ㄱㄹ is parallel to ㄴㄷ, and ㄱㄴ, ㄱㅁ and ㄱㄹ are all the same length. How big is ㉮?
- ①64 degrees
- ②108 degrees
- ③54 degrees
- ④55 degrees
- ⑤72 degrees
Show solution
③54 degrees- ㄱㄴㅁ is isosceles, so angle ㄱㅁㄴ is 72 degrees as well.
- Alternate angles are equal, so angle ㄹㄱㅁ is 72 too.
- ㄱㅁㄹ is isosceles as well, so ㉮ is (180 − 72) ÷ 2 = 54.
- A straight line is 180, so angle ㄹㅁㄷ follows and ㉯ is 55 degrees.
- 5 · ★5A rhombus of paper is folded as shown. How big is angle ㄱㄴㄹ?
- ①31 degrees
- ②66 degrees
- ③45 degrees
- ④21 degrees
- ⑤69 degrees
Show solution
④21 degrees- Neighbouring angles of a rhombus add to 180, so the folded corner is 180 − 111 = 69.
- The angles of a triangle add to 180, so the remaining angle is 180 − 69 − 66.
- A folded angle equals the angle it covers, so that angle appears twice.
- Taking both away from 111 leaves angle ㄱㄴㄹ as 21 degrees.
Where people usually go wrong
- Measuring between parallel lines along a slant rather than along a perpendicular.
- Answering with the larger of two angles that add to 180.
- Using 180 degrees where a full turn of 360 is needed.
- Not halving after the folded angle and the angle it covers are found to be equal.
- Taking a folded angle away once when it appears on both sides of the crease.
- Adding the angle carried across a parallel instead of taking it off.
- Counting only across, or only down, when counting rectangles round a star.
- Missing the tilted squares in a dot array.
Practice these in your own notebook
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