Pythagorean Theorem Practice Problems
Find the missing side of a right triangle. The early problems come out whole; the later ones leave a radical you have to simplify rather than round.
What this problem type covers
Each problem gives two sides of a right triangle and asks for the third. The first bands use Pythagorean triples so the answer is a whole number; later bands leave an irrational answer that has to be written as a simplified radical.
Example problems
One example from each difficulty band, with worked solutions.
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- 1 · ★1A right triangle has legs of 60 and 63. Find the hypotenuse.
- ①c = 123
- ②c = 60
- ③c = 7569
- ④c = 3√41
- ⑤c = 87
Show solution
⑤c = 87- Use the Pythagorean theorem: a2 + b2 = c2
- Substitute the known sides: 602 + 632 = c2
- So the unknown side squared is 3600 + 3969 = 7569.
- Taking the positive square root: c = 87
- 2 · ★2A right triangle has legs of 12 and 35. Find the hypotenuse.
- ①c = 1369
- ②c = 37
- ③c = 12
- ④c = 47
- ⑤c = √1081
Show solution
②c = 37- Use the Pythagorean theorem: a2 + b2 = c2
- Substitute the known sides: 122 + 352 = c2
- So the unknown side squared is 144 + 1225 = 1369.
- Taking the positive square root: c = 37
- 3 · ★3A right triangle has a hypotenuse of 50 and one leg of 48. Find the other leg.
- ①b = 2
- ②b = 98
- ③b = 196
- ④b = 14
- ⑤b = 2√1201
Show solution
④b = 14- Use the Pythagorean theorem: a2 + b2 = c2
- Substitute the known sides: 482 + b2 = 502
- So the unknown side squared is 2500 − 2304 = 196.
- Taking the positive square root: b = 14
- 4 · ★4A right triangle has legs of 4 and 2. Find the hypotenuse.
- ①c = 20
- ②c = 2√5
- ③c = 6
- ④c = 4
- ⑤c = 2√3
Show solution
②c = 2√5- Use the Pythagorean theorem: a2 + b2 = c2
- Substitute the known sides: 42 + 22 = c2
- So the unknown side squared is 16 + 4 = 20.
- Taking the positive square root: c = 2√5
- 5 · ★5A right triangle has legs of 5 and 3. Find the hypotenuse.
- ①c = 34
- ②c = 8
- ③c = 4
- ④c = 5
- ⑤c = √34
Show solution
⑤c = √34- Use the Pythagorean theorem: a2 + b2 = c2
- Substitute the known sides: 52 + 32 = c2
- So the unknown side squared is 25 + 9 = 34.
- Taking the positive square root: c = √34
Where people usually go wrong
- Treating the hypotenuse as just another leg. a² + b² = c² only holds with c as the hypotenuse — the longest side.
- Adding when you should subtract. Finding a leg means c² − a², not c² + a².
- Forgetting the square root at the end. c² = 169 is not the answer; c = 13 is.
- Rounding √50 to 7.07. The exact answer is 5√2, and rounding early loses it for good.
- Leaving a radical unsimplified. √72 and 6√2 are the same number, but only one is finished.
Practice these in your own notebook
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